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7x^2=13x+6
We move all terms to the left:
7x^2-(13x+6)=0
We get rid of parentheses
7x^2-13x-6=0
a = 7; b = -13; c = -6;
Δ = b2-4ac
Δ = -132-4·7·(-6)
Δ = 337
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-\sqrt{337}}{2*7}=\frac{13-\sqrt{337}}{14} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+\sqrt{337}}{2*7}=\frac{13+\sqrt{337}}{14} $
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